The claim
Transfer entropy is I(X_{t+1}; Y_t^{(l)} | X_t^{(k)}) (TERM-057), and for Gaussian data it is half Granger causality (TERM-058), so what follows holds of the Granger measure there too. By the consistency equations of any partial information decomposition with the two sources Y’s past and X’s past, a conditional mutual information is the source’s unique information plus the synergy of the two. The redundancy drops out, and the synergy comes in (Williams and Beer, THEORY-712). Only the decomposition’s two-term split is needed here, not their I_min redundancy measure.
If “flow from Y to X” means information in X’s next value attributable to Y’s past alone, as James, Barnett and Crutchfield define it (THEORY-707), then flow is at most the unique part, and transfer entropy overstates it by the synergy. Where several sources fix the target jointly, each pairwise transfer entropy can be zero. Conditioning on the other sources (causation entropy, complete transfer entropy) brings their joint bit back, but credits it to each source in full, so it is counted once per source.
The two examples
Both recomputed exactly on 2026-10-17 (a scratchpad script with an I_min PID; NOTE-945), and again under Harder, Salge and Polani’s I_red and Bertschinger et al.’s unique information, with the same values (NOTE-944, NOTE-937), and under Ince’s I_ccs (NOTE-968).
- Overstating flow. X_t i.i.d. uniform bits, Y_t = X_{t−1} ⊕ Y_{t−1}. T_{X→Y} = I(Y_t; X_{t−1} | Y_{t−1}) = 1 bit. But I(Y_t; X_{t−1}) = 0 and I(Y_t; Y_{t−1}) = 0: neither past alone says anything about Y_t. The co-information is −1, and the PID gives 0 redundant, 0 unique to each, 1 synergistic. The whole bit is joint.
- Understating influence. X, Y i.i.d. uniform, Z_t = X_{t−1} ⊕ Y_{t−1}. Both T_{X→Z} and T_{Y→Z} are 0, and every pairwise information is 0, yet Z is fixed by the two. The causation entropies, each conditioning on the other source, are 1 bit each, so the one bit is counted twice.
Lizier et al.’s rule 18 is the same structure in a cellular automaton (THEORY-702): where the centre cell is 0 the update is L ⊕ R, apparent transfer entropy from each neighbour is 0 and complete transfer entropy is 1 bit from each. That reading of their case is the record’s; they read the contrast as complex against chaotic dynamics.
The first process is Williams and Beer’s coupled pair at d = 1, where they call the bit “state-dependent transfer”. The two papers agree on the decomposition. They disagree only on whether that part is to be called transfer.
What it does not say
- That transfer entropy is wrong as a predictive measure. As predictive improvement it is exactly what THEORY-641 and THEORY-700 say: a likelihood-ratio limit, and twice Granger causality for Gaussian data.
- That a nonzero transfer entropy shows no influence. In example 1, intervening on X_{t−1} does change Y_t, so Ay and Polani’s interventional flow credits X (THEORY-710). What fails is localizing the bit to X alone, not the existence of an effect. Prediction against intervention is CLAIM-333’s separate question.
- What the unique part is. It has no agreed measure. In general every number beyond the two-term split depends on a choice of redundancy function, though Bertschinger et al. prove the split itself for any bivariate decomposition (THEORY-705, Remark 14). In the record’s examples the numbers are the same under I_min and under their measure, because the target’s own past says nothing about its next value there (NOTE-937).
- That directed information escapes this. James, Barnett and Crutchfield say it inherits the flaw. Its lagged part is full-history transfer entropy (THEORY-711), so it does at least that far.
Note of 2026-10-21: synergy in the target
A6 and A7 of the exchange of 2026-10-20 called the three-bit chain of THEORY-820 “synergistic” without citing this claim. Its arrangement differs from the one here. This claim’s synergy is between a source and the target’s past. In the chain, the micro past’s bit is carried by the target’s two components jointly (A′ ⊕ B′ = C_t), and by the chain rule T(A, B) = I(X⃗; A′ | A⃗, B⃗) + I(X⃗; B′ | A⃗, B⃗, A′) = 0 + 1 bit (checked). So transfer entropy onto a joint target can be positive where it is zero onto each component, the dual of this claim’s “read zero from sources that jointly fix the target”. A7 rightly did not commit to a PID measure.