Source
Blackwell (1953), LIT-781, read in NOTE-595: the definitions in §1 and Theorem 3, “α ≻ β implies α ⊃ β”. The paper quotes the result from Blackwell (1951), unread here. The re-derivation below does not depend on either proof.
Definitions
- Experiment. For a parameter set Θ, an experiment α is a family (α_θ)_{θ∈Θ} of probability measures on one measurable outcome space X. THEORY-156 quotes it: “an n-tuple of probability measures on a common space, one per state”. Two experiments compared must share Θ, and they need not share an outcome space.
- Garbling. β on Y is a garbling of α on X when there is a Markov kernel K from X to Y with β_θ(B) = ∫ K(B | x) α_θ(dx) for every θ and every measurable B. Blackwell’s “α is sufficient for β”, written α ≻ β.
- Decision problem and risk. An action space A, a loss L(θ, a) bounded and measurable in a, and a decision rule for β, which is a Markov kernel δ from Y to A. The rule’s risk at θ is R_β(δ, θ) = ∫∫ L(θ, a) δ(da | y) β_θ(dy). The risk vector is (R_β(δ, θ))_{θ∈Θ}.
- Informativeness order. α ⊃ β when, in every decision problem, every risk vector attainable with β is attainable with α. THEORY-156 quotes the finite-Θ form: “for every closed bounded convex set A of loss vectors, every risk vector attainable with β is attainable with α”.
The claim, and its proof
If β is a garbling of α, then α ⊃ β.
Take any decision problem and any rule δ for β. Define a rule for α by first garbling and then applying δ: δ’(C | x) = ∫ δ(C | y) K(dy | x). This is a Markov kernel from X to A, being a composition of two kernels. Its risk at θ is
R_α(δ’, θ) = ∫ [∫∫ L(θ, a) δ(da | y) K(dy | x)] α_θ(dx) = ∫∫ L(θ, a) δ(da | y) [∫ K(dy | x) α_θ(dx)] = ∫∫ L(θ, a) δ(da | y) β_θ(dy) = R_β(δ, θ).
The exchange of integrals is Fubini’s theorem. It applies because L is bounded and measurable, and every kernel is a probability measure in its first argument. The second line is the definition of the garbling. So δ’ attains with α exactly the risk vector δ attains with β, at every θ. Since δ and the problem were arbitrary, α ⊃ β. ∎
Nothing in the proof uses finiteness of Θ, X, Y or A. It uses only that rules may be randomized, so that a composition of kernels is a rule, and that losses are bounded, so the integrals exist.
What it does not say
- The converse. That α ⊃ β implies a garbling exists is THEORY-717 for finitely many states and outcomes (Active), and THEORY-156 in general (Proposed).
- Anything about a restricted receiver. The decision-maker may use any rule. A receiver limited to a class of rules can do better with a garbling than with the original (CLAIM-199, CLAIM-225).
- How much worse an incomparable experiment is. The order is qualitative. That is Le Cam’s deficiency, unread here (LIT-778).